Vayudoot Aviation

1.
At 60° N the scale of a direct Mercator chart is 1 : 3 000 000.What is the scale at the equator?

1 : 3 000 000

1 : 6 000 000

1 : 3 500 000

1 : 1 500 000

2.
In which two months of the year is the difference between the transit of the Apparent Sun and Mean Sun across the Greenwich Meridian the greatest?

June and December

April and August

February and November

March and September

3.
What is the time required to travel along the parallel of latitude 60° N between meridians 010° E and 030° W at a groundspeed of 480 kt?

2 HR 30 MIN

1 HR 15 MIN

5 HR 00 MIN

1 HR 45 MIN

4.
61.4.7.0 (4483) An aircraft was over 'A' at 1435 hours flying direct to 'B'.Given:Distance 'A' to 'B' 2900 NMTrue airspeed 470 ktMean wind component 'out' +55 ktMean wind component 'back' -75 ktSafe endurance 9 HR 30 MIN The distance from 'A' to the Point of Safe Return (PSR) 'A' is

1611 NM

2141 NM

2844 NM

1759 NM

5.
Given: TAS = 135 kt,HDG (°T) = 278,W/V = 140/20ktCalculate the Track (°T) and GS?

279 - 152 kt

275 - 150 kt

282 - 148 kt

283 - 150 kt

6.
An aircraft is descending down a 12% slope whilst maintaining a GS of 540 kt.The rate of descent of the aircraft is approximately

4500 FT/MIN

3900 FT/MIN

650 FT/MIN

6500 FT/MIN

7.
For a landing on runway 23 (227° magnetic) surface W/V reported by the ATIS is 180/30kt. VAR is 13°E. Calculate the cross wind component?

15 kt

26 kt

22 kt

20 kt

8.
An aircraft travels 2.4 statute miles in 47 seconds. What is its groundspeed?

131 kt

183 kt

209 kt

160 kt

9.
An aircraft in the northern hemisphere is making an accurate rate one turn to the right. If the initial heading was 135°, after 30 seconds the direct reading magnetic compass should read

less than 225°

225°

more or less than 225° depending on the pendulous suspension used

more than 225°

10.
In which of the following situations is the FMC present position of a B737-400 Electronic Flight Instrument System likely to be least accurate? a) Just after take-off b) At

At top of descent

Just after take-off

On final approach

At top of climb

11.
Given: GS = 435 kt.Distance from A to B = 1920 NM.What is the time from A to B?

4 HR 25 MIN

3 HR 26 MIN

3 HR 25 MIN

4 HR 10 MIN

12.
The scale on a Lambert conformal conic chart

is constant along a parallel of latitude

is constant across the whole map

is constant along a meridian of longitude

varies slightly as a function of latitude and longitude

13.
As the INS position of the departure aerodrome, coordinates 35°32.7'N 139°46.3'W are input instead of 35°32.7'N 139°46.3'E. When the aircraft subsequently passes point 52°N 180°W, the longitude value shown on the INS will be

080° 27.4'E

080° 27.4'W

099° 32.6'E

099° 32.6'W

14.
Given: Distance 'A' to 'B' is 90 NM,Fix obtained 60 NM along and 4 NM to the right of course.What heading alteration must be made to reach 'B'?

8° Left

16° Left

4° Left

12° Left

15.
From the departure point, the distance to the point of equal time is

inversely proportional to the sum of ground speed out and ground speed back

inversely proportional to ground speed back

proportional to the sum of ground speed out and ground speed back

inversely proportional to the total distance to go

16.
In an Inertial Navigation System (INS), Ground Speed (GS) is calculated:

from TAS and W/V from Air Data Computer (ADC)

from TAS and W/V from RNAV data

by integrating gyro precession in N/S and E/W directions respectively

by integrating measured acceleration

17.
On a direct Mercator projection, at latitude 45° North, a certain length represents 70 NM. At latitude 30° North, the same length represents approximately

70 NM

86 NM

57 NM

81 NM

18.
On a Direct Mercator chart at latitude of 45°N, a certain length represents a distance of 90 NM on the earth. The same length on the chart will represent on the earth, at latitude 30°N, a distance of

45 NM

78 NM

73.5 NM

110 NM

19.
Given:True Heading = 090° TAS = 180 ktGS = 180 ktDrift 5° rightCalculate the W/ V?

360° / 15 kt

180° / 15 kt

190° / 15 kt

010° / 15 kt

20.
Concerning direct reading magnetic compasses, in the northern hemisphere, it can be said that

on a Westerly heading, a longitudinal deceleration causes an apparent turn to the North

on a Westerly heading, a longitudinal acceleration causes an apparent turn to the South

on an Easterly heading, a longitudinal acceleration causes an apparent turn to the South

on an Easterly heading, a longitudinal acceleration causes an apparent turn to the North

21.
Given:Distance 'Q' to 'R' 1760 NMGroundspeed 'out' 435 ktGroundspeed 'back' 385 ktThe time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is

106 MIN

114 MIN

102 MIN

110 MIN

22.
An aircraft at FL120, IAS 200kt, OAT -5° and wind component +30kt, is required to reduce speed in order to cross a reporting point 5 MIN later than planned. Assuming flight conditions do not change, when 100 NM from the reporting point IAS should be reduced to

169 kt

165 kt

174 kt

159 kt

23.
At 47° North the chart distance between meridians 10° apart is 5 inches. The scale of the chart at 47° North approximates

1 : 8 000 000

1 : 6 000 000

1 : 3 000 000

1 : 2 500 000

24.
Given:Distance 'A' to 'B' 2346 NMGroundspeed 'out' 365 ktGroundspeed 'back' 480 ktThe time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is

219 MIN

197 MIN

290 MIN

167 MIN

25.
An aircraft is planned to fly from position 'A' to position 'B',distance 320 NM, at an average GS of 180 kt. It departs 'A' at 1200 UTC.After flying 70 NM along track from 'A', the aircraft is 3 MIN ahead of planned time.Using the actual GS experienced, what is the revised ETA at 'B'?

1401 UTC

1340 UTC

1333 UTC

1347 UTC

26.
The principle of 'Schuler Tuning' as applied to the operation of Inertial Navigation Systems/ Inertial Reference Systems is applicable to

both gyro-stabilised platform and 'strapdown' systems

only to 'strapdown' laser gyro systems

both gyro-stabilised and laser gyro systems but only when operating in the non 'strapdown' mode

only gyro-stabilised systems

27.
Given:True Heading = 180° TAS = 500 ktW/V 225° / 100 ktCalculate the GS?

600 kt

535 kt

450 kt

435 kt

28.
On a Lambert chart (standard parallels 37°N and 65°N), with respect to the straight line drawn on the map between A ( N49° W030°) and B (N48° W040°), the

rhumb line is to the north, the great circle is to the south

great circle is to the north, the rhumb line is to the south

great circle and rhumb line are to the north

great circle and rhumb line are to the south

29.
When accelerating on an easterly heading in the Northern hemisphere, the compass card of a direct reading magnetic compass will turn

anti-clockwise giving an apparent turn toward the north

anti-clockwise giving an apparent turn toward the south

clockwise giving an apparent turn toward the north

clockwise giving an apparent turn toward the south

30.
Assuming zero wind, what distance will be covered by an aircraft descending 15000 FT with a TAS of 320 kt and maintaining a rate of descent of 3000 FT/MIN?

38.4 NM

26.7 NM

16.0 NM

19.2 NM

31.
Some inertial reference and navigation systems are known as ""strapdown"". This means that

gyros and accelerometers need satellite information input to obtain a vertical reference

the gyroscopes and accelerometers become part of the unit's fixture to the aircraft structure

gyros and accelerometers are mounted on a stabilised platform in the aircraft

only the gyros, and not the accelerometers, become part of the unit's fixture to the aircraft structure

32.
A ground feature appears 30° to the left of the centre line of the CRT of an airborne weather radar. If the heading of the aircraft is 355° (M) and the magnetic variation is 15° East, the true bearing of the aircraft from the feature is

160°

130°

220°

310°

33.
The constant of the cone, on a Lambert chart where the convergence angle between longitudes 010°E and 030°W is 30°, is

0.64

0.50

0.75

0.40

34.
On a Direct Mercator chart, a rhumb line appears as a

small circle concave to the nearer pole

straight line

curve convex to the nearer pole

spiral curve

35.
Given:ILS GP angle = 3.5 DEG,GS = 150 kt.What is the approximate rate of descent?

1000 FT/MIN

700 FT/MIN

900 FT/MIN

800 FT/MIN

36.
What is the name given to an Inertial Reference System (IRS) which has the gyros and accelerometers as part of the unit's fixture to the aircraft structure?

Solid state

Strapdown

Ring laser

Rigid

37.
An aircraft travels 100 statute miles in 20 MIN, how long does it take to travel 215 NM?

100 MIN

50 MIN

80 MIN

90 MIN

38.
The value of magnetic variation

cannot exceed 90°

has a maximum of 180°

must be 0° at the magnetic equator

varies between a maximum of 45° East and 45° West

39.
The main reason that day and night, throughout the year, have different duration, is due to the

inclination of the ecliptic to the equator

gravitational effect of the sun and moon on the speed of rotation of the earth

earth's rotation

relative speed of the sun along the ecliptic

40.
Civil twilight is defined by

sun upper edge tangential to horizon

sun altitude is 12° below the celestial horizon

sun altitude is 6° below the celestial horizon

sun altitude is 18° below the celestial horizon

41.
Given:For take-off an aircraft requires a headwind component of at least 10 kt and has a cross-wind limitation of 35 kt. The angle between the wind direction and the runway is 60°, Calculate the minimum and maximum allowable wind speeds?

20 kt and 40 kt

18 kt and 50 kt

12 kt and 38 kt

15 kt and 43 kt

42.
In order to maintain an accurate vertical using a pendulous system, an aircraft inertial platform incorporates a device

without damping and a period of 84.4 MIN

with damping and a period of 84.4 MIN

with damping and a period of 84.4 SEC

without damping and a period of 84.4 SEC

43.
Which of the following statements concerning the earth's magnetic field is completely correct?

The earth's magnetic field can be classified as transient, semi-permanent or permanent

Dip is the angle between total magnetic field and vertical field component

At the earth's magnetic equator, the inclination varies depending on whether the geograhic equator is north or south of the magnetic equator

The blue pole of the earth's magnetic field is situated in North Canada

44.
Deviation applied to magnetic heading gives

magnetic track

true heading

magnetic course

compass heading

45.
730 FT/MIN equals

1.6 m/sec

2.2 m/sec

3.7 m/sec

5.2 m/sec

46.
In a remote indicating compass system the amount of deviation caused by aircraft magnetism and electrical circuits may be minimised by

mounting the detector unit in the wingtip

positioning the master unit in the centre of the aircraft

using a vertically mounted gyroscope

the use of repeater cards

47.
Given: TAS = 480 kt,HDG (°T) = 040°,W/V = 090/60kt.Calculate the Track (°T) and GS?

034 - 445 kt

028 - 415 kt

032 - 425 kt

036 - 435 kt

48.
An island appears 60° to the left of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 276° with the magnetic variation (VAR) 10°E?

226°

086°

046°

026°

49.
Given: Pressure Altitude 29000 FT, OAT -55°C. Calculate the Density Altitude?

26000 FT

27500 FT

31000 FT

33500 FT

50.
The drift of the azimuth gyro on an inertial unit induces an error in the position given by this unit. ""t"" being the elapsed time.The total error is

proportional to t

proportional to the square of time, t²

sinusoîdal

proportional to t/2

Question Bank

Questions for Indigo gen NAV 4090-4604

At 60° N the scale of a direct Mercator chart is 1 : 3 000 000.What is the scale at the equator?

In which two months of the year is the difference between the transit of the Apparent Sun and Mean Sun across the Greenwich Meridian the greatest?

What is the time required to travel along the parallel of latitude 60° N between meridians 010° E and 030° W at a groundspeed of 480 kt?

61.4.7.0 (4483) An aircraft was over 'A' at 1435 hours flying direct to 'B'.Given:Distance 'A' to 'B' 2900 NMTrue airspeed 470 ktMean wind component 'out' +55 ktMean wind component 'back' -75 ktSafe endurance 9 HR 30 MIN The distance from 'A' to the Point of Safe Return (PSR) 'A' is

Given: TAS = 135 kt,HDG (°T) = 278,W/V = 140/20ktCalculate the Track (°T) and GS?

An aircraft is descending down a 12% slope whilst maintaining a GS of 540 kt.The rate of descent of the aircraft is approximately

For a landing on runway 23 (227° magnetic) surface W/V reported by the ATIS is 180/30kt. VAR is 13°E. Calculate the cross wind component?

An aircraft travels 2.4 statute miles in 47 seconds. What is its groundspeed?

An aircraft in the northern hemisphere is making an accurate rate one turn to the right. If the initial heading was 135°, after 30 seconds the direct reading magnetic compass should read

In which of the following situations is the FMC present position of a B737-400 Electronic Flight Instrument System likely to be least accurate? a) Just after take-off b) At

Given: GS = 435 kt.Distance from A to B = 1920 NM.What is the time from A to B?

The scale on a Lambert conformal conic chart

As the INS position of the departure aerodrome, coordinates 35°32.7'N 139°46.3'W are input instead of 35°32.7'N 139°46.3'E. When the aircraft subsequently passes point 52°N 180°W, the longitude value shown on the INS will be

Given: Distance 'A' to 'B' is 90 NM,Fix obtained 60 NM along and 4 NM to the right of course.What heading alteration must be made to reach 'B'?

From the departure point, the distance to the point of equal time is

In an Inertial Navigation System (INS), Ground Speed (GS) is calculated:

On a direct Mercator projection, at latitude 45° North, a certain length represents 70 NM. At latitude 30° North, the same length represents approximately

On a Direct Mercator chart at latitude of 45°N, a certain length represents a distance of 90 NM on the earth. The same length on the chart will represent on the earth, at latitude 30°N, a distance of

Given:True Heading = 090° TAS = 180 ktGS = 180 ktDrift 5° rightCalculate the W/ V?

Concerning direct reading magnetic compasses, in the northern hemisphere, it can be said that

Given:Distance 'Q' to 'R' 1760 NMGroundspeed 'out' 435 ktGroundspeed 'back' 385 ktThe time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is

An aircraft at FL120, IAS 200kt, OAT -5° and wind component +30kt, is required to reduce speed in order to cross a reporting point 5 MIN later than planned. Assuming flight conditions do not change, when 100 NM from the reporting point IAS should be reduced to

At 47° North the chart distance between meridians 10° apart is 5 inches. The scale of the chart at 47° North approximates

Given:Distance 'A' to 'B' 2346 NMGroundspeed 'out' 365 ktGroundspeed 'back' 480 ktThe time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is

An aircraft is planned to fly from position 'A' to position 'B',distance 320 NM, at an average GS of 180 kt. It departs 'A' at 1200 UTC.After flying 70 NM along track from 'A', the aircraft is 3 MIN ahead of planned time.Using the actual GS experienced, what is the revised ETA at 'B'?

The principle of 'Schuler Tuning' as applied to the operation of Inertial Navigation Systems/ Inertial Reference Systems is applicable to

Given:True Heading = 180° TAS = 500 ktW/V 225° / 100 ktCalculate the GS?

On a Lambert chart (standard parallels 37°N and 65°N), with respect to the straight line drawn on the map between A ( N49° W030°) and B (N48° W040°), the

When accelerating on an easterly heading in the Northern hemisphere, the compass card of a direct reading magnetic compass will turn

Assuming zero wind, what distance will be covered by an aircraft descending 15000 FT with a TAS of 320 kt and maintaining a rate of descent of 3000 FT/MIN?

Some inertial reference and navigation systems are known as ""strapdown"". This means that

A ground feature appears 30° to the left of the centre line of the CRT of an airborne weather radar. If the heading of the aircraft is 355° (M) and the magnetic variation is 15° East, the true bearing of the aircraft from the feature is

The constant of the cone, on a Lambert chart where the convergence angle between longitudes 010°E and 030°W is 30°, is

On a Direct Mercator chart, a rhumb line appears as a

Given:ILS GP angle = 3.5 DEG,GS = 150 kt.What is the approximate rate of descent?

What is the name given to an Inertial Reference System (IRS) which has the gyros and accelerometers as part of the unit's fixture to the aircraft structure?

An aircraft travels 100 statute miles in 20 MIN, how long does it take to travel 215 NM?

The value of magnetic variation

The main reason that day and night, throughout the year, have different duration, is due to the

Civil twilight is defined by

Given:For take-off an aircraft requires a headwind component of at least 10 kt and has a cross-wind limitation of 35 kt. The angle between the wind direction and the runway is 60°, Calculate the minimum and maximum allowable wind speeds?

In order to maintain an accurate vertical using a pendulous system, an aircraft inertial platform incorporates a device

Which of the following statements concerning the earth's magnetic field is completely correct?

Deviation applied to magnetic heading gives

730 FT/MIN equals

In a remote indicating compass system the amount of deviation caused by aircraft magnetism and electrical circuits may be minimised by

Given: TAS = 480 kt,HDG (°T) = 040°,W/V = 090/60kt.Calculate the Track (°T) and GS?

An island appears 60° to the left of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 276° with the magnetic variation (VAR) 10°E?

Given: Pressure Altitude 29000 FT, OAT -55°C. Calculate the Density Altitude?

The drift of the azimuth gyro on an inertial unit induces an error in the position given by this unit. ""t"" being the elapsed time.The total error is