Email
info@vayudootaviation.com
Phone No
+91 7276526726
become a pilot
Home
About us
courses
CPL
ATPL
RTR(A)
Airline Cadet Program
IGRUA Entrance Prep
B.Sc. Aviation
Pilot Training
INDIA
USA
CANADA
SOUTH AFRICA
NEW ZEALAND
EUROPE
Aircraft Type-Rating
Airbus A320
Boeing 737
Blogs
contact
CPL Test Series
Question Bank
Questions for DISTANCE ON EARTH AND SURFACE
Answer the following questions
Test Mode
Training Mode
1.
An A/C takes off from (50°S 004°E) and flies on track of 090°for 2 hrs and then alters its track to 180° and later it alters its track to 270° after flying for 1 hr 27 min, it crosses the meridian by 4°E. If G/S of the A/C was constant at 380 Kts throughout the flight, what was the flying time of the aircraft on second leg?
- [2 × 380 = D LONG' × 50° 1. 1.45 × 380 = D LONG' × COS Θ 2. (2 × 380) / (1.45 × 380) = (DLONG × 60 × COS 50°) / (DLONG × 60 × COSΘ). COS Θ = COS50° × 1.45 / 2. Θ = 62°13'. DIFFERENCE BETWEEN LATITUDES = 12°13'. DISTANCE = 733 NM. TIME = 733/380 = 1 HR 59 MIN.]
- [2 × 380 = D LONG' × 50° 1. 1.45 × 380 = D LONG' × COS Θ 2. (2 × 380) / (1.45 × 380) = (DLONG × 60 × COS 50°) / (DLONG × 60 × COSΘ). COS Θ = COS50° × 1.45 / 2. Θ = 62°13'. DIFFERENCE BETWEEN LATITUDES = 12°13'. DISTANCE = 733 NM. TIME = 733/380 = 1 HR 57 MIN.]
2. Great Circle Distant - fill in the blanks: A Latitude Great Circle Distances - 53°25'N, Longitude Great Circle Distances - 108°00'E, B Latitude Great Circle Distances - 47°17'N, Longitude Great Circle Distances - 108°00'E, D Lat - ________ , Distance (nm) - _________ .
- [D LAT - 6°08', DISTANCE (NM) - 368.]
- [D LAT - 6°08', DISTANCE (NM) - 348.]
3. The "departure" between positions 60°N160°E and 60°N "X" is 900nm. what is the longitude of "X"?
170°W
145°E
175°E
4. Great Circle Distant - fill in the blanks: A Latitude Great Circle Distances - 37°27'S, Longitude Great Circle Distances - 049° 21'E, B Latitude Great Circle Distances - 43°21'S, Longitude Great Circle Distances - 049°21'E, D Lat - ________ , Distance (nm) - _________ .
- [D LAT - 5°54', DISTANCE (NM) - 354.]
- [D LAT - 5°54', DISTANCE (NM) - 352.]
5. An aircraft at latitude 02°20'N tracks 180°(T) for 8=685km. on completion of the flight the latitude will be
03°50'S
04°30'S
04°10'S
6. Great Circle Distant - fill in the blanks: A Latitude Great Circle Distances - 78°47'N, Longitude Great Circle Distances - 035°45'W, B Latitude Great Circle Distances - 84°35'N, Longitude Great Circle Distances - 144°15'E, D Lat - ________ , Distance (nm) - _________ .
- [D LAT - 16°38', DISTANCE (NM) - 938.]
- [D LAT - 16°38', DISTANCE (NM) - 998.]
7. Great Circle Distant - fill in the blanks: A Latitude Great Circle Distances - 10°21'S, Longitude Great Circle Distances - 113° 47'W, B Latitude Great Circle Distances - 05°17'N, Longitude Great Circle Distances - 113°47'W, D Lat - ________ , Distance (nm) - _________
- [D LAT - 15°38', DISTANCE (NM) - 928.]
- [D LAT - 15°38', DISTANCE (NM) - 938.]
8. The circumference of the parallel of latitude at 60°N is approximately
34641nm
10800nm
18706nm
9. An aircraft at position 60°N005°W tracks 090°(T) for 315km. on completion of the flight the longitude will be
000°40'E
000°15'E
002°10'W
10. Position A 60°N020°W, Position B 60°NO21°W and Position C 59°N020°W. What are, respectively, the distances from A to B and from A to C?
30nm and 60nm
52nm and 60nm
60nm and 52nm
11. Great Circle Distant - fill in the blanks: A Latitude Great Circle Distances - 49°00'S, Longitude Great Circle Distances - 012° 25'E, B Latitude Great Circle Distances - 45°00's, Longitude Great Circle Distances - 012°25'E, D Lat - ________ , Distance (nm) - _________ .
- [D LAT - 4°00', DISTANCE (NM) - 242.]
- [D LAT - 4°00', DISTANCE (NM) - 240.]
12. How many feet are there in 1 sm?
3280 ft
5280 ft
6080 ft
13. How many feet are there in a nm?
6080 ft
3280 ft
1000 ft
14. A flight is to be made from "A" 49°S180°E/@ to "b" 58°S180°E/W. the distance in kilometers from "A" to "B" is approximately
1000
804
1222
15. Rhumb Line Distance - fill in the blanks: A Latitude Rhumb Line (departure) Distance - 47°30'N, Longitude Rhumb Line (departure) Distance - 025°00'W, B Latitude Rhumb Line (departure) Distance - 47°30'N, Longitude Rhumb Line (departure) Distance - 044°28'W, D Long - ________ , Distance (nm) - _________ .
- [D LONG - 11.08' , DISTANCE (NM) - 738.1.]
- [D LONG - 11.08' , DISTANCE (NM) - 788.1.]
16. How many feet are equivalent to 9, 5 km?
31,160 ft
57,760 ft
50,160 ft
17. What is the longitude of a position 6NM to the east of 58°42'N094°00'W?
093°48.5'W
093°53.1'W
094°12.0'W
18. An aircraft at latitude 10°S flies north at a GS of 890km/h. what will its latitude be after 1.5h?
12°15'N
02°00'N
22°00'N
19. In international aviation the following units are used for horizontal distance
meters, kilometers and nautical miles.
meters, statute miles and nautical miles.
kilometers, statute miles and nautical miles.
20.
An A/C takes off from A (30°S 060°E) and flies in northerly direction for 600 nm, thereafter in easterly direction for 600 nm. Thereafter southerly direction for 600 nm, thereafter westerly direction for 600 nm. Find final position of A/C in nm. East or of starting position.
- [DEPARTURE A = 600 NM, 600 = D LONG' × COS (20°). D LONG - 10° 38'. NEW POSITION A = 070° 38'. DEPARTURE B = ?. = D LONG' × COS (30°) = 10°38' × 60 × COS 30° = 553 NM. THEREFORE THE A/C TRAVELS WEST FOR 600 NM, IT WILL REACH 47NM TO THE WEST STARTING POINT.]
- [DEPARTURE A = 600 NM, 600 = D LONG' × COS (20°). D LONG - 10° 38'. NEW POSITION A = 070° 38'. DEPARTURE B = ?. = D LONG' × COS (30°) = 10°38' × 60 × COS 30° = 553 NM. THEREFORE THE A/C TRAVELS WEST FOR 600 NM, IT WILL REACH 49NM TO THE WEST STARTING POINT.]
21.
An A/C takes off from (45° 40' N 176° 36°E) and flies on true track of 090°for 1480 kms. Find lat - long of destination.
- [DEPARTURE = D LONG × 60 × COS LAT. 1480 KMS = (1480 ÷ 1.85) NMS = 800 NMS. D LONG = [800/60XCOS(45°40') ]=19° 04'. LONG = 176°36'+19°04' = 360° - 195°40' = 164°20'W.]
- [DEPARTURE = D LONG × 60 × COS LAT. 1480 KMS = (1480 ÷ 1.85) NMS = 800 NMS. D LONG = [800/60XCOS(45°40') ]=19° 04'. LONG = 176°36'+19°04' = 360° - 195°40' = 164°20'S.]
22. When dealing with heights and altitudes in international aviation, we use the following units
feet, kilometer and decimals of nautical mile.
meter and feet.
feet and yard.
23. Rhumb Line Distance - fill in the blanks: A Latitude Rhumb Line (departure) Distance - 21°00'N, Longitude Rhumb Line (departure) Distance - 010°43'E, B Latitude Rhumb Line (departure) Distance - 21°00'N, Longitude Rhumb Line (departure) Distance - 016°17'E, D Long - ________ , Distance (nm) - _________
- [D LONG - 334', DISTANCE (NM) - 313.8.]
- [D LONG - 334', DISTANCE (NM) - 311.8.]
24. An aircraft departing A(N40° 00' E080° 00') flies a constant true track of 270° at a ground speed of 120 kts. What are the coordinates of the position reached in 6 HR?
N40° 00' E060° 00'.
N40° 00' E068° 10'.
N40° 00' E064° 20'.
25.
An A/C takes off from X (39° 42' N 105° 20'E) for Y(39° 42'N 178' 35' E). Find R/L Distance.
- [D'LONG = 178°35'E - 105° 20'E = 73° 15'. DEPARTURE = D LONG × 60 × COS LAT = 73°15' × COS (39°42'), 4395 × COS 39°42' = 3,381.5 NM.]
- [D'LONG = 178°35'E - 105° 20'E = 73° 15'. DEPARTURE = D LONG × 60 × COS LAT = 73°15' × COS (39°42'), 4395 × COS 39°42' = 4,381.5 NM.]
26.
An A/C takes off from A (27° 13'N 024° 37'E) to B (27°13'N 094° 37' W). Find departure.
- [D'LONG = 094° 37'W+024°37 E = 119° 14'. DEPARTURE = D LONG IN MINS × COS LAT = 119° 14'×60 ×COS 27°13'. = 6361.93. = 6342 NM.]
- [D'LONG = 094° 37'W+024°37 E = 119° 14'. DEPARTURE = D LONG IN MINS × COS LAT = 119° 14'×60 ×COS 27°13'. = 6361.93. = 6362 NM.]
27. What is the time required to travel along the parallel of latitude 60°N between meridians 010°E and 030°W at a groundspeed of 480Kt?
01:15
02:30
01:45
28. An aircraft at latitude 10°North flies south at a groundspeed of 445km/h. what will be its latitude after 3h?
12°15'S
03°50'S
02°00'S
29. Position A is located on the equator at longitude 130°00'E. Position B is located 100NM from A on a bearing of 225°(T). The coordinates of position B are
01°11'S 131°11'E
01°11'N 131°11'E
01°11'S 128°49'E
30. Position A 45°N, ?°E, Position B 45°N, 45°15'E, Distance A-B=280NM. B is to the East of A , Required : longitude of position A?
49°57'E
38°39'E
51°51'E
31. Consider the following statements
the any position on the surface of the earth, the length of 1 of arc east/west is equal to the length 1 minute of urc north/south in the same position on a perfect sphere.
both statements are correct.
the exact length 1 minute of are varies a little from position to position because the earth radius vary.
32. Units used for, measuring vertical distances (altitude, elevation and height) are meters and feet. In India, feet is used. For horizontal distances units used are NMs. KMs & meters. In India NMs are used above 2NMs and meters for short distances.
Poles
Equator
45° Latitude
33. Position A 00°N100°E Position B is 240°(T), 200NM from A. What is the position of B?
01°40'S097°07'E
01°40'N097°07'E
01°40'N101°40'E
34.
An a/c takes off from place X (45°20'N 010° 05'E) and flies in R/L direction of 270° for 800 nm. Find lat - long of destination.
- [DEPARTURE = D LONG' × COS LAT, 800 NM = D LONG' × COS (45°20'N), D LONG = 800 ÷ 0.7029 = 1138' = 18°58'. LONG Y = 18° 58' - 10°05' = 008° 53' W. LAT LONG = 45° 20'N 08° 53' S.]
- [DEPARTURE = D LONG' × COS LAT, 800 NM = D LONG' × COS (45°20'N), D LONG = 800 ÷ 0.7029 = 1138' = 18°58'. LONG Y = 18° 58' - 10°05' = 008° 53' W. LAT LONG = 45° 20'N 08° 53' W.]
35.
Departure = 250 nm, D long = 4°50', find latitude.
- [DEPARTURE = D LONG' × COS LAT. 250 = 4°50' × 60 × COS Θ. COS Θ = 250/60 × 4°50'. COST LAT = 0.86 = 30°47' N/S.]
- [DEPARTURE = D LONG' × COS LAT. 250 = 4°50' × 60 × COS Θ. COS Θ = 250/60 × 4°50'. COST LAT = 0.86 = 30°41' N/S.]
36. If an aeroplane was to circle around the Earth following parallel 60°N at a ground speed of 480kt. In order to circle around the Earth along the equator in the same amount of time, it should fly at a ground speed of:
550kt
240kt
960kt
37. In order to fly from position A (10°00'N030°00'W) to position B (30°00'N050°00'W), maintaining a constant true course, it is necessary to fly
the great-circle route
a rhumb line track
a straight line plotted on a lambert chart
38.
An A/C takes off from 10° N 175°E it flies in southerly direction for 600 nm. Thereafter in easterly direction for 600 nm. Thereafter in southerly direction for 600 nm. Find lat - long of destination.
- [FIRST POINT : 000° N 175°E, SECOND POINT:000°N 175°W, DESTINATION: 10°S 175°S.]
- [FIRST POINT : 000° N 175°E, SECOND POINT:000°N 175°W, DESTINATION: 10°S 175°W.]
39. A nautical mile is defined as
the average length of a 1' arc of longitude and a 1' arc of latitude.
the average length of a 1 minute arc of a meridian.
1855 meters.
40. Rhumb Line Distance - fill in the blanks: A Latitude Rhumb Line (departure) Distance - 52°00'N, Longitude Rhumb Line (departure) Distance - 21°31'W, B Latitude Rhumb Line (departure) Distance - 52°00'N, Longitude Rhumb Line (departure) Distance - 010°17'E, D Long - ________ , Distance (nm) - _________
- [D LONG - 1908' DISTANCE (NM) - 1134.7.]
- [D LONG - 1908' DISTANCE (NM) - 1174.7.]
41. Kilometer is defined as
1 1/10000 part of the meridian length from equator to the pole.
the mean length of a 1/40000 part of the equator.
0,454 nautical mile.
42.
An A/C takes off from (48°5' N 001° W) and flies on track of 270° for 2 hrs 10 min and then alters its track to 360° and later it alters its track to 090°, after flying for 1 hr 32 min, it crosses the meridian by 1° W. If G/S of the A/C was 420 Kts throughout the flight, what was the flying time on second leg.
- [2.10 × 420 = D LONG' × 48° 5' 1. 1.32 × 420 = D LONG' × COS Θ 2. (2.10 × 420) / (1.32 × 420) = (DLONG × 60 × COS 48°5') / (DLONG × 60 × COS Θ). COS Θ = (COS 48°5' × 1.32) / 2.10. Θ = 61°46'. DIFFERENCE BETWEEN LATITUDES = 13° 41'. DISTANCE = 13°41' × 60 = 821 NM. TIME = 821/ 420 = 1 HR 59 MIN.]
- [2.10 × 420 = D LONG' × 48° 5' 1. 1.32 × 420 = D LONG' × COS Θ 2. (2.10 × 420) / (1.32 × 420) = (DLONG × 60 × COS 48°5') / (DLONG × 60 × COS Θ). COS Θ = (COS 48°5' × 1.32) / 2.10. Θ = 61°46'. DIFFERENCE BETWEEN LATITUDES = 13° 41'. DISTANCE = 13°41' × 60 = 821 NM. TIME = 821/ 420 = 1 HR 57 MIN.]
43. Rhumb Line Distance - fill in the blanks: A Latitude Rhumb Line (departure) Distance - 13°00'S, Longitude Rhumb Line (departure) Distance - 175°17'E, B Latitude Rhumb Line (departure) Distance - 13°00'S, Longitude Rhumb Line (departure) Distance - 168°31'W, D Long - ________ , Distance (nm) - _________
- [D LONG - 972', DISTANCE (NM) - 947.]
- [D LONG - 972', DISTANCE (NM) - 949.]
44. An aircraft departs from position A (04°10'S178°22'W) and flies northward following the meridian for 2950NM. It then flies westward along the parallel of latitude for 382NM to position B. The coordinates of position are?
45°00'N168°22'W
53°20'N172°38'E
45°00'N172°38'E
45.
Two A/C A and B take off from X (53°N 004°E') for point Y (60°N 016°W). A/C A tiles due north till 60° latitude and then due west to Y. A/C B flies due west till 016°W than to Y. Which A/C travels shorter and by how many nautical miles.
- [DEPARTURE A = D LONG' × COS LAT = 20 × 60 × COS 60° = 600 NM. DEPARTURE B = D LONG' × COS LAT = 20 × 60 × COS 53° = 722 NM. A TRAVELS LESS BY 126 NM.]
- [DEPARTURE A = D LONG' × COS LAT = 20 × 60 × COS 60° = 600 NM. DEPARTURE B = D LONG' × COS LAT = 20 × 60 × COS 53° = 722 NM. A TRAVELS LESS BY 122 NM.]
46.
A/C flying from place X (27°27'N 030° 24' E) to Y(27° 27' N 108° 47' E). Find rhumb line Distance.
- [D'LONG = 108° 47'E - 030° 24'E = 78° 23'. DEP = (78°×60' + 23')× COS 27°27' = 4703×COS 27°27' = 4173 NM.]
- [D'LONG = 108° 47'E - 030° 24'E = 78° 23'. DEP = (78°×60' + 23')× COS 27°27' = 4703×COS 27°27' = 4163 NM.]
47. Rhumb Line Distance - fill in the blanks: A Latitude Rhumb Line (departure) Distance - 49°00'S, Longitude Rhumb Line (departure) Distance - 012°25'E, B Latitude Rhumb Line (departure) Distance - 49°00'S, Longitude Rhumb Line (departure) Distance - 025°45'E, D Long - ________ , Distance (nm) - _________
- [D LONG - 800', DISTANCE (NM) - 524.8.]
- [D LONG - 800', DISTANCE (NM) - 523.8.]
48.
An A/C takes off from X (32° 48'S 178° 10'W) and flies on true westerly track for 450 nm. Find lat long of Y.
- [D'LONG = DEP/60XCOS(LAT) = 450/60XCOS(32°48') = 450 ÷ 0.8405 = 535'. = 8°55' = 360° - (178°10'W + 008°55'W) = 172° 55'E. LAT - LONG = (32°48'S 172°55'S).]
- [D'LONG = DEP/60XCOS(LAT) = 450/60XCOS(32°48') = 450 ÷ 0.8405 = 535'. = 8°55' = 360° - (178°10'W + 008°55'W) = 172° 55'E. LAT - LONG = (32°48'S 172°55'E).]
49. I nautical mile equals
1855 meters.
6976 feet.
0,869 statute mile.
50. An aircraft flies a great circle track from 56°N070°W to 62°N110°E. The total distance traveled is?
5420nm
2040nm
3720nm
Submit
Make New Set