Vayudoot Aviation

1. UTC at 93°30' W is 0100 hrs. Find ZT

- [ZT 92°30' ÷ 15 = 6. ZT = 01:00-06:00 = 19:00 HRS.]

- [ZT 92°30' ÷ 15 = 6. ZT = 01:00-06:00 = 18:00 HRS.]

2. Mumbai's position is 19 deg. 05 min N and 73 deg. 00 min. East. There is a place exactly North of Mumbai whose latitude is 21 deg. N and long. 73 deg. 00 min. East When IST in Mumbai is 1200 hrs. then the IST at the other place will be

1122

1200

1238

3. Observer's meridian 40°N 11° 20'E. LMT 13:00 hrs Find LMT at (i) 060°N 121°21' E (ii) 53°S 110°23'W

- [UTC = LMT - D LONG/15 = 1300 - (11°20'/15) DIFF = 45 MIN = 13:00 HRS - 45 MTS = 12:15 HRS AT 0° E/W (UTC) (I) AT 121° 21'E 8 HR 05 MIN LMT = 12:15 + 8:05 = 20:20 HR, (II) DIFF = 7 HR 21 MIN LMT = 12:15 - 7:21 = 04:54 HR.]

- [UTC = LMT - D LONG/15 = 1500 - (11°20'/15) DIFF = 45 MIN = 13:00 HRS - 45 MTS = 12:15 HRS AT 0° E/W (UTC) (I) AT 121° 21'E 8 HR 05 MIN LMT = 12:15 + 8:05 = 20:20 HR, (II) DIFF = 7 HR 21 MIN LMT = 12:15 - 7:21 = 04:54 HR.]

4. ZT at 52° 30'E is 12:00 hrs. Find UTC and LMT

- [52°30' ÷ 13 = 3. UTC = 09:00 HRS LMT = 11:30 HRS]

- [52°30' ÷ 13 = 3. UTC = 09:00 HRS LMT = 12:30 HRS]

5. A is at longitude 01230E and B is at longitude 04315E LMT in B is 1749. What is the LMT in A?

1952

1546

1706

6.
LMT at A (42° 23/N 105° E) is 01:00 hrs on 12/02. Find UTC and LMT at place B which is (23° 45'S 62°W)

- [AT 105°E LMT = 01:00 AT 0° DIFF = 07 HR (I) TIME 1800 UTC ON PREVIOUS DAY(11/2) (II) AT 62° W DIFF = 4 HR 08 MIN. TIME 13:52 PREVIOUS DAY (11/3)]

- [AT 105°E LMT = 01:00 AT 0° DIFF = 07 HR (I) TIME 1800 UTC ON PREVIOUS DAY(11/2) (II) AT 62° W DIFF = 4 HR 08 MIN. TIME 13:52 PREVIOUS DAY (11/2)]

7. I.S.T. and the LMT of a place can be the same only when

the Longitude of the place is 82 deg. 30 min. East

all the above

the place is in India

8. The sun rises at 50°N and 025°E on the 25th January at 0254UTC. On the same day what time does it rise at 50°N and 040°W?

0254 UTC.

2154 UTC.

0714 UTC.

9. On the 27th of February, at 52°S and 040°E, the sunrise is at 0243UTC on the same day, at 52°S and 035°W, the sunrise is at

0523 LMT

0243 LMT

0743 LMT

10. What is the meaning of the term "standard time"?

it is an expression for local mean time

it is another term for UTC

it is the time set by the legal authorities for a country or part of a country

11. Local Mean Time of a place is the time lapsed since the transit of the mean sun over

the prime meridian

its antemeridian

its meridian

12. When GMT at CHennai 1300N 8300E is 110 hrs. The IST at Kolkatta 2000N 8830E will be

1630

1100

1122

13. Find LMT, ZT and IST (82.5°E) at 30°N 90° E if UTC is 02:00 hrs

- [UTC = 02:00 HRS, ZT = 08:00 HRS, LMT = 08:00 HRS, IST = 07:30 HRS]

- [UTC = 02:00 HRS, ZT = 08:00 HRS, LMT = 08:00 HRS, IST = 06:30 HRS]

14. At 10 hr 10 min at 160° E, difference between zone time and LMT will be

Zone time will be ahead of LMT by 20 min

LMT will be ahead of ZT by 20 min

Zone time will be ahead of LMT by 40 min

15. The LMT at a place in India is 0400. If the position of the place is 10 deg. N and 78 deg. East, the IST at that place will be

0342

0418

0400

16. What does 5 hours 50 minutes and 20 seconds change of longitude represent?

87°35

80°05

35°15

17. Consider the following statements on sunrise and sunset

in November sunset occurs earlier at 4500S than at 4500N.

at equator sunrise and sunset occur at quite regular times throughout the year.

in May sunrise occurs later 4500N than at 4500S.

18. LMT at 55° 29' N000° E is 1200 hrs on 01 March. Find UTC at 23° 23' S180°E

- [12:00 HRS 01 MARCH.]

- [12:00 HRS 02 MARCH.]

19. The times given for sunrise, sunset, morning and evening twilight in the air almanac

are given in LMT.

are given in UTC.

are given in standard time.

20. An a/c is crossing IDL from 150°E to 108°W at 0000 UTC, at destination

LMT is behind and date is ahead.

Both LMT and date are behind

Date is behind and LMT is ahead

21. The local mean time at longitude 095°20'W at 0000UTC is

1738:40 previous day

0621:20 previous day

1738:40 same day

22.
An a/c takes off from X (35°S 168°W) for place Y (32°S 164°15'E) It flies for 8h 20', time of departure X is 2145 hr LMT 2nd June. Find ETA at Y in LMT.

- [FLIES FOR 8 HR 20 MIN. TIME OF DEPARTURE = 21:45 HRS ON 02/06 LMT AT ARRIVAL AT PLACE OF DEPARTURE LMT = 21:45 HRS + 08:20 HRS = 06:05 HRS ON 03/06. UTC = 06:05 HRS + 168 ÷15=17:17 HRS ON 03/06. LMT AT Y = 17:17 HRS + 164°15' ÷15 = 04:14 HRS. LMT AT Y = 04:14 HRS 04 JUNE.]

- [FLIES FOR 8 HR 20 MIN. TIME OF DEPARTURE = 21:45 HRS ON 02/06 LMT AT ARRIVAL AT PLACE OF DEPARTURE LMT = 21:45 HRS + 08:20 HRS = 06:05 HRS ON 03/06. UTC = 06:05 HRS + 168 ÷15=17:17 HRS ON 03/06. LMT AT Y = 17:17 HRS + 164°15' ÷15 = 04:14 HRS. LMT AT Y = 04:14 HRS 04 JULY.]

23. Mean time has been introduced in order to

have one fixed time to be used within the border of a country.

introduce a constant measurement of time, independent of the daily variations in the movement of the sun as observed from the earth.

compensate for the irregularities of the speed of rotation of the earth around it is axis.

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