Vayudoot Aviation

1. Given: Distance 'A' to 'B' 3600 NM, Groundspeed 'out' 395 kt, Groundspeed 'back' 300 kt. The time from'A' to the Point of Equal Time (PET) between 'A' and 'B' is ?

288 MIN.

236 MIN.

323 MIN.

283 MIN.

2. What is the distance to the point of safe endurance if an aircraft has a TAS of 400 knots and a safe enndurance of 10 hours, if the wind component on the outbound leg is 75 knots headwind?

1805 nm.

1930 nm.

1654 nm.

1994 nm.

3. What is the distance to the point of safe endurance if an aircraft has a TAS of 375 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1850 nm.

1825 nm.

1854 nm.

1842 nm.

4. Given: Distance 'A' to 'B' 2700 NM, Groundspeed 'out' 465 kt, Groundspeed 'back' 515 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

159 MIN.

177 MIN.

165 MIN.

183 MIN.

5. Given: Distance 'A' to 'B' 3623 NM, Groundspeed 'out' 390 kt, Groundspeed 'back' 330 kt. The time from 'A' t the Point of Equal Time (PET) between 'A' and 'B' is?

323 MIN.

255 MIN.

238 MIN.

288 MIN.

6. An aircraft was over'Q' at 1320 hours flying direct to'R'. Given: Distance 'Q' to 'R' 3016 NM, True airspeed 480 kt, Mean wind component 'out' -90 kt, Mean wind component 'back' +75 kt, Safe endurance 10:00 HR. The distance from 'Q' to the Point of Safe Return (PSR) 'Q' is?

2290 NM.

1310 NM.

1510 NM.

2370 NM.

7. What is the distance from 'Q' to the Point of Safe Return (PSR) for an aircraft that was over 'Q' at 1400 hours flying direct to 'R', given the following data? Distance 'Q' to 'R' 3050 nm, True airspeed 480 kt, Safe endurance 10 Hours, if the mean wind component 'outbound' -90 kt, and the mean wind component 'homebound' is +75 kt.

2375 nm.

1530 nm.

2290 nm.

2190 nm.

8. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 6 hours, if the wind component on the outbound leg is 20 knots headwind?

2.9 hours.

3.2 hours.

3.4 hours.

2.6 hours.

9. What is the distance to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots tailwind?

1458 nm.

1625 nm.

1548 nm.

1505 nm.

10. Given: Distance 'Q' to 'R' 2467 NM, Groundspeed 'out' 500 kt, Groundspeed 'back 400 kt, Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

2175 NM.

2111 NM.

2167 NM.

2001 NM.

11. An aircraft is flying at a TAS of 375 knots over a stretch of water between 2 airfields 500 nm apart. What is the distance from the first airfield to the equal time point (ETP) if the wind component is 60 knots head?

350 nm.

280 nm.

290 nm.

300 nm.

12. Given: Distance 'A' to 'B' 3623 NM, Groundspeed 'out' 370 kt, Groundspeed 'back' 300 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

263 MIN.

238 MIN.

323 MIN.

288 MIN.

13. What is the distance to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 30 knots headwind?

1625 nm.

1485 nm.

1505 nm.

1554 nm.

14. Given: Distance 'A' to 'B' 2346 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

290 MIN.

219 MIN.

167 MIN.

197 MIN.

15. Given: Distance 'A' to 'B' 2484 NM, Mean groundspeed 'out' 420 kt, Mean groundspeed 'back' 500 kt, Safe endurance 08 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

1908 NM.

1736 NM.

1630 NM.

1940 NM.

16. Given: Distance 'A' to 'B' 2600 NM, Groundspeed 'out' 395 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

237 MIN.

267 MIN.

217 MIN.

190 MIN.

17. Two points A and B are 1200 NM apart. TAS = 480 kt. On the flight between A and B the equivalent headwinds is -20 kt. On the return leg between B and A, the equivalent headwind is +40 Kt. What distance from A, along the route A to B, is the Point of Equal Time (PET)?

655 NM.

624 NM.

670 NM.

600 NM.

18. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 435 kt, Groundspeed 'back' 385 kt. The time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

102 MIN.

106 MIN.

114 MIN.

110 MIN.

19. An aircraft is flying at a TAS of 300 knots over a stretch of water between 2 airfields 500 nm apart. What is the distance from the first airfield to the equal time point (ETP) if the wind component is 60 knots head?

250 nm.

200 nm.

300 nm.

280 nm.

20. Given: Distance 'Q' to 'R' 2160 NM, Groundspeed 'out' 535 kt, Groundspeed 'back 585 kt, Safe endurance 6 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1613 NM.

1775 NM.

1677 NM.

1667 NM.

21. Given: Distance 'A' to 'B' 1973 NM, Groundspeed 'out' 430 kt, groundspeed 'back' 385 kt, Safe endurance 7 HR 20 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

1698 NM.

1490 NM.

1664 NM.

1422 NM.

22. Given: Distance 'A' to 'B' 900 NM, Groundspeed 'out' 220 kt, Groundspeed 'back' 250 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

278 MIN.

295 MIN.

271 MIN.

290 MIN.

23. Given: Distance 'Q' to 'R' 1650 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is ?

1867 NM.

1813 NM.

1767 NM.

1742 NM

24. An aircraft was over 'Q' at 1620 hours flying direct to 'R'. Given: Distance 'Q' to 'R' 3050 NM, True airsped 480 kt, Mean wind component 'out' -90 kt, Mean wind component 'back' +75kt, Safe endurance 10;00 HR. The distance from 'Q' to the Point of Safe Return (PSR) 'Q' is?

2270 NM.

2290 NM.

1910 NM.

2310 NM.

25. Given: Distance 'A' to 'B' 3600 NM, Groundspeed 'out' 378 kt, Groundspeed 'back' 400 kt. The time 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

283 MIN.

294 MIN.

288 MIN.

323 MIN.

26. What is the distance to B from the equal-time-pint given the following data? Distance A to B is 650 nm TAS is 320 kt. Wind component A - B is -15 kt Wind component B - A is +15 kt

280 nm.

309 nm.

297 nm.

375 nm.

27. Given: Distance 'Q' to 'R' 1960 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 470 kt, Safe endurance 7 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1542 NM.

1353 NM.

1538 NM.

1513 NM.

28. Given: Distance 'Q' to 'R' 1970 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 485 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1973 NM.

1964 NM.

2013 NM.

2072 NM.

29. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 360 kt. The time 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

114 MIN.

109 MIN.

116 MIN.

104 MIN.

30. An aircraft was over 'A' at 1735 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2750 NM, True airspeed 470 kt, Mean wind component 'out' +55 kt, Mean wind component 'back' -75 kt. The ETA for reaching the Point of Equal Time (PET) between 'A' and 'B' is?

1921.

1944.

1950.

1846.

31. Given: Distance 'A' to 'B' 2900 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 380 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

249 MIN.

290 MIN.

295 MIN.

272 MIN.

32. Given: Distance 'A' to 'B' 500 NM, Groundspeed 'out' 120 kt, Groundspeed 'back' 130 kt, Safe endurance 6 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

203 MIN.

215 MIN.

220 MIN.

209 MIN.

33. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 40 hours, if the wind component on the outbound leg is 50 knots headwind?

1.9 hours.

2.1 hours.

2.3 hours.

1.1 hours.

34. What is the distance to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1458 nm.

1554 nm.

1505 nm.

1625 nm.

35. What is the time to the point of safe return (PSR) if the distance from A to B is 2500 nautical miles, the outbound groundspeed in 375 knots, the homebound groundspeed is 480 knots, and safe endurance is 9 hours 30 minutes?

390 min.

319 min.

320 min.

309 min.

36. An aeroplane is flying at TAS 345 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?

171 NM.

156 NM.

163 NM.

188 NM.

37. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 7 hours, if the wind component on the outbound leg is 65 knots headwind?

4.32 hours.

4.11 hours.

3.91 hours.

4.26 hours.

38. Given: Distance 'Q' to 'R' 1750 NM, Groundspeed 'out' 475 kt, Groundspeed 'back' 365 kt. The time from 'Q' t the Point of Equal Time (PET) between 'Q' and 'R' is?

92 MIN.

91 MIN.

97 MIN.

106 MIN.

39. An aircraft was over 'A' at 1735 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2950 NM, True airspeed 470 kt, Mean wind component 'out' +55 kt, Mean wind component 'back' -75 kt, Safe endurance 9 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?is?

2844 NM.

1611 NM.

1759 NM.

2141 NM.

40. An aircraft was over 'A' at 1700 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2900 NM, True airspeed 480 kt, Mean wind component 'out +55 kt, Mean wind component 'back' -75 kt. The ETA for reaching the Point of Equal Time (PET) between 'A' and 'B' is?

1946.

1920.

1821.

1934.

41. Given: Distance 'A' to 'B' 2500 NM, Groundspeed 'out' 370 kt, Groundspeed 'back' 480 kt. Safe endurance 6 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

215 MIN.

220 MIN.

229 MIN.

230 MIN.

42. What is the distance to the point of safe endurance if an aircraft has a TAS of 200 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 85 knots headwind?

819 nm.

854 nm.

505 nm.

865 nm.

43. Given: Distance 'A' to 'B' 2484 NM, Groundspeed 'out' 420 kt, Groundspeed 'back' 500 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

183 MIN.

193 MIN.

173 MIN.

163 MIN.

44. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 280 kt on a track of 090°, if the W/V is 045°/50kt?

188 nm.

175 nm.

158 nm.

135 nm.

45. What is the distance to the point of safe endurance if an aircraft has a TAS of 350 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1754 nm.

1713 nm.

1725 nm.

1605 nm.

46. An aircraft was over 'Q' at 1545 hours flying direct to 'R'. Given: Distance 'Q' to 'R" 3016 NM, True airspeed 550 kt, Mean wind component 'out -90 kt, Mean wind component 'back' +75 kt, Safe endurance 10;00 HR. The distance from 'Q' to the Point of Safe Return (PSR) 'Q' is?

2650 NM.

2710 NM

2670 NM.

2610 NM.

47. Two points A and B are 1500 NM apart. TAS = 490 kt. On the flight between A and B the equivalent headwind is -20 kt. On the return leg between B and A, the equivalent headwind is +40 kt. What distance from A, along the route A to B, is the Point of Equal Time (PET)?

750 NM.

650 NM

795 NM.

800 NM.

48. An aeroplane is flying at TAS 180 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?

176 NM.

85 NM.

88 NM.

56 NM.

49. Given: Distance 'A' to 'B' 2346 N, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

197 MIN.

209 MIN.

290 MIN.

219 MIN.

50. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 370 kt. The time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

121 MIN.

116 MIN.

106 MIN.

100 MIN.

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