Vayudoot Aviation

1. An aircraft was over 'A' at 1630 hours flying direct to 'B'. Given: Distance 'A' to 'B' 3000 NM, True airspeed 490 kt, Mean wind component 'out +55 kt, Mean wind component 'back' -75 kt. Safe endurance 9 HR 30 MIN.The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

2259 NM.

2254 NM.

2238 NM.

2211 NM.

2. What is the distance to B from the equal-time-point given the following data? Distance A to B is 560 nm TAS is 200 kt. Wind component A - B is -15 kt Wind component B - A is +15 kt

259.0 nm.

380.5 nm.

170.5 nm.

375.5 nm.

3. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 6 hours, if the wind component on the outbound leg is 20 knots headwind?

2.9 hours.

2.6 hours.

3.2 hours.

3.4 hours.

4. Given: Distance 'A' to 'B' 2000 NM, Groundspeed 'out' 420 kt, Groundspeed 'back' 480 kt, Safe endurance 3 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

190 MIN.

149 MIN.

112 MIN.

195 MIN.

5. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 40 hours, if the wind component on the outbound leg is 50 knots headwind?

1.9 hours.

1.1 hours.

2.3 hours.

2.1 hours.

6. An aircraft was over 'A' at 1735 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2750 NM, True airspeed 470 kt, Mean wind component 'out' +55 kt, Mean wind component 'back' -75 kt. The ETA for reaching the Point of Equal Time (PET) between 'A' and 'B' is?

1950.

1921.

1846.

1944.

7. For a distance of 2000 NM between Q and R, a ground speed "out" of 375 kt, a ground speed "back" of 475 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is?

1930 NM.

1565 NM.

1676 NM.

1632 NM.

8. Given: Distance 'A' to 'B' 2100 NM, Groundspeed 'out' 430 kt, Groundspeed 'back' 365 kt, Safe endurance 7 HR 20 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is ?

1540 NM.

1228 NM.

1420 NM.

1464 NM.

9. What is the time to the point of safe return (PSR) if the distance from A to B is 3000 nautical miles, the outbound groundspeed in 350 knots, the homebound groundspeed is 460 knots, and safe endurance is 8 hours 30 minutes?

290 Min.

229 Min.

190 min.

209 min.

10. Given: Distance 'A' to 'B' 2500 NM, Groundspeed 'out' 370 kt, Groundspeed 'back' 480 kt. Safe endurance 6 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

220 MIN.

215 MIN.

230 MIN.

229 MIN.

11. What is the distance from 'Q' to the Point of Safe Return (PSR) for an aircraft that was over 'Q' a 1500 hours flying direct to 'R', given the following data? Distance 'Q' to 'R' 3050 nm, True airspeed 435 kt, Safe endurance 10 Hours, if the mean wind component 'outbound' -90kt, and the mean wind component 'homebound' is +75 kt.

2190 nm.

2530 nm.

2058 nm.

2075 nm.

12. Given: Distance 'A' to 'B' 2600 NM, Mean Groundspeed 'out' 380 kt, Mean Groundspeed 'back' 475 kt. Safe endurance 08 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

1794 NM.

1978 NM

1730 NM.

1691 NM.

13. What is the distance to the point of safe endurance if an aircraft has a TAS of 375 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1854 nm.

1842 nm.

1825 nm.

1850 nm.

14. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 260 kt on a track of 090°, if the W/V is 045°/50kt?

158 nm.

128 nm.

188 nm.

175 nm.

15. Given: Distance 'Q' to 'R' 1650 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is ?

1813 NM.

1742 NM

1767 NM.

1867 NM.

16. An aircraft was over'Q' at 1320 hours flying direct to'R'. Given: Distance 'Q' to 'R' 3016 NM, True airspeed 480 kt, Mean wind component 'out' -90 kt, Mean wind component 'back' +75 kt, Safe endurance 10:00 HR. The distance from 'Q' to the Point of Safe Return (PSR) 'Q' is?

1310 NM.

2290 NM.

2370 NM.

1510 NM.

17. An aircraft was over 'Q' at 1545 hours flying direct to 'R'. Given: Distance 'Q' to 'R" 3016 NM, True airspeed 550 kt, Mean wind component 'out -90 kt, Mean wind component 'back' +75 kt, Safe endurance 10;00 HR. The distance from 'Q' to the Point of Safe Return (PSR) 'Q' is?

2610 NM.

2650 NM.

2710 NM

2670 NM.

18. Given: Distance 'Q' to 'R' 2550 NM, Groundspeed 'out' 550 kt, Groundspeed 'back' 400 kt. Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'A' is?

2250 NM.

2200 NM.

2267 NM.

2275 NM.

19. Given: Distance 'Q' to 'R' 1970 NM, Groundspeed 'out' 436 kt, Groundspeed 'back' 485 kt. Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

2013 NM.

2066 NM.

2079 NM.

1964 NM.

20. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 360 kt. The time 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

116 MIN.

114 MIN.

109 MIN.

104 MIN.

21. Given: Distance 'Q' to 'R' 1860 NM, Groundspeed 'out' 420 kt, Groundspeed 'back' 350 kt. Safe endurance 7 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1336 NM.

1538 NM.

1432 NM.

1353 NM.

22. An aeroplane is flying at TAS 180 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?

88 NM.

176 NM.

85 NM.

56 NM.

23. Given: Distance 'A' to 'B' 1973 NM, Groundspeed 'out' 430 kt, Groundspeed 'back' 385 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

162 MIN.

181 MIN.

145 MIN.

130 MIN.

24. Given: Distance 'Q' to 'R' 1950 NM, Groundspeed 'out' 455 kt, Groundspeed 'back' 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1838 NM.

1867 NM.

1877 NM.

1713 NM.

25. What is the time to the point of safe endurance if an aircraft has a TAS of 100 knots and a safe endurance of 5 hours, if the wind component on the outbound leg is 20 knots headwind?

2.0 hours.

3.1 hours.

1.9 hours.

3.0 hours.

26. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 5 hours, if the wind component on the outbound leg is 30 knots headwind?

2.75 hours.

2.3 hours.

3.6 hours.

2.9 hours.

27. What is the distance to the point of safe endurance if an aircraft has a TAS of 350 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1714 nm.

1725 nm.

1750 nm.

1754 nm.

28. Given: Distance 'A' to 'B' 2346 N, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

209 MIN.

197 MIN.

219 MIN.

290 MIN.

29. Given: Distance 'A' to 'B' 1950 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 385 kt, Safe endurance 7 HR 20 MIN. The distance from 'A' t the Point of Safe Return (PSR) 'A' is?

1438 NM.

1464 NM.

1498 NM.

1422 NM

30. Given: Distance 'Q' to 'R' 2160 NM, Groundspeed 'out' 535 kt, Groundspeed 'back 585 kt, Safe endurance 6 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1613 NM.

1667 NM.

1677 NM.

1775 NM.

31. Given: Distance 'A' to 'B' 2484 NM, Groundspeed 'out' 420 kt, Groundspeed 'back' 500 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

183 MIN.

193 MIN.

173 MIN.

163 MIN.

32. For a distance of 2100 NM between Q and R, a ground speed "out" of 365 kt, a ground speed "back" of 435 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is?

155 NM.

1588 NM.

1532 NM.

1630 NM.

33. Given: Distance 'A' to 'B' 1500 NM, Groundspeed 'out' 120 kt, Groundspeed 'back' 180 kt, Safe endurance 10 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

399 MIN.

390 MIN.

378 MIN.

395 MIN.

34. Given: Distance 'Q' to 'R' 1650 NM, Groundspeed 'out' 465 kt, Groundspeed 'back' 385 kt. Safe endurance 9 HR. The distance from 'A' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1842 NM.

1896 NM.

1867 NM.

1853 NM.

35. Given: Distance 'A' to 'B' 2900 NM, Groundspeed 'out' 420 kt, Groundspeed 'back' 400 kt. Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

249 MIN.

259 MIN.

290 MIN.

272 MIN.

36. What is the distance to the point of safe endurance if an aircraft has a TAS of 350 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?

1725 nm.

1713 nm.

1754 nm.

1605 nm.

37. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 7 hours, if the wind component on the outbound leg is 65 knots headwind?

4.11 hours.

4.32 hours.

3.91 hours.

4.26 hours.

38. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 280 kt on a track of 090°, if the W/V is 045°/50kt?

188 nm.

175 nm.

135 nm.

158 nm.

39. Given: Distance 'A' to 'B' 2400 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B" is?

190 MIN.

197 MIN.

224 MIN.

267 MIN.

40. An aeroplane is flying at TAS 345 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?

156 NM.

171 NM.

163 NM.

188 NM.

41. Given: Distance 'A' to 'B' 2750 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

297 MIN.

209 MIN.

290 MIN.

229 MIN.

42. Given: Distance 'A' to 'B' 2450 NM, Groundspeed 'out' 350 kt, Groundspeed 'back' 385 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?

220 MIN.

195 MIN.

182 MIN.

201 MIN.

43. Two points A and B are 1300 NM apart. TAS = 485 kt. On the flight between A and B the equivalent headwind is -20 kt. On the return leg between B and A, the equivalent headwind is +40 kt. What distance from A. along the route A to B, is the Point of Equal Time (PET)?

690 NM.

647 NM.

655 NM.

676 NM.

44. An aircraft was over 'A' at 1435 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2900 NM, True airspeed 470 kt, Mean wind component 'out +55 kt, Mean wind component 'back' -75 kt, Safe endurance 9 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

1611 NM.

2844 NM.

2141 NM.

1759 NM.

45. Given: Distance 'A' to 'B' 2900 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 380 kt, Safe endurance 8 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?

290 MIN.

249 MIN.

272 MIN.

295 MIN.

46. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 435 kt, Groundspeed 'back' 385 kt. The time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

114 MIN.

106 MIN.

102 MIN.

110 MIN.

47. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 370 kt. The time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is?

121 MIN.

116 MIN.

106 MIN.

100 MIN.

48. Given: Distance 'Q' to 'R' 1860 NM, Groundspeed 'out' 400 kt, Groundspeed 'back 370 kt, Safe endurance 7 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?

1345 NM.

1442 NM.

1538 NM.

1313 NM.

49. An aircraft was over 'A' at 1600 hours flying direct to 'B'. Given: Distance 'A' to 'B' 3000 NM, True airspeed 390 kt, Mean wind component 'out +55 kt, Mean wind component 'back' - 75 kt, Safe endurance 9 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?

1795 NM.

1752 NM.

1711 NM.

2254 NM.

50. What is the time to the point of safe return (PSR) if the distance from A to B is 2500 nautical miles, the outbound groundspeed in 375 knots, the homebound groundspeed is 480 knots, and safe endurance is 9 hours 30 minutes?

390 min.

320 min.

319 min.

309 min.

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